Problem 15.28 in the textbook and solutions manual

[robert zellmer]

Chapter 15 end-of-chapter problem 15.28 asks you to add two
eqns to get a third and determine the Kp given Kc values for
the two given eqns.  However, the solutions manual gives the
Kc for the final equation and does not convert it to Kp.
The answer of 9.523 x 10^-31 is correct for the Kc value.
(9.5 x 10^-31 to the correct s.f.).

To get Kp you need to use the eqn,

Kp = Kc * (RT)^(delta n)

The (delta n) is the change in moles of gas.  For this question
it would 2 - 3 = -1

Kp = Kc * (RT)^(-1) = (9.523 x 10^-31)*{(0.0821)(298)}^(-1)

Kp = 3.89 x 10^-32

Dr. Zellmer
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