Problem 15.28 in the textbook and solutions manual

[Zellmer, Robert]

Chapter 15 end-of-chapter problem 15.28 asks you to add two
eqns to get a third and determine the Kp given Kc values for
the two given eqns.  The final eqn is:

N2(g)  +  O2(g)  +  Br2(g)  ---->  2 NOBr(g)

However, the solutions manual gives the Kc for the final
equation and does not convert it to Kp.  The answer of
9.523 x 10^-31 is correct for the Kc value.  (9.5 x 10^-31 to
the correct # of s.f.).

To get Kp you need to use the eqn,

Kp = Kc * (RT)^(delta n)

The (delta n) is the change in moles of gas.  For this question
it would 2 - 3 = -1

Kp = Kc * (RT)^(-1) = (9.523 x 10^-31)*{(0.0821)(298)}^(-1)

Kp = 3.89 x 10^-32

Dr. Zellmer
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