Errors in Ch 21 Self-Assessment Exercises
Zellmer, Robert
zellmer.1 at osu.edu
Wed Apr 19 13:00:49 EDT 2023
A fellow student contacted me about problems with three SAEs in Ch 21.
Section 21.1:
SAE 21.4
What particle is produced during the following decay process? Mn-56 decays to
Fe-56
56 56 0
Mn ---> Fe + e
25 26 -1
A beta particle is ejected from the nucleus as a neutron converts into a
proton and electron (which is ejected from the nucleus). The electron
in this case is called a beta particle.
Answer (a) is beta particle (β-)
The answer given when you click on the answer box is "a) alpha particle, (β-)".
It's not "alpha" but "beta".
Section 21.2:
SAE 21.7
The final two steps in the decay chain for uranium-238 are:
Bi-210 ---> Po-210 ---> Pb-206
Lead-206 is a stable isotope. What are the radioactive decay processes for
these two steps?
The answer given is:
e. electron capture followed by alpha emission
There is a misprint in the explanation.
The answer should be:
e. beta emission followed by alpha emission
SAE 21.8
Which of the following statements about the stability of nuclides is false?
The answer given is:
e. A nucleus that decays via electron capture has a neutron-to-proton ratio
that is lower than expected for stability.
This is true.
The correct answer should be (the false statement):
a. Nuclides in the belt of stability always have the same ratio of neutrons
to protons". It actually increases from around 1 for lighter nuclides to 1.5
as the nuclides get larger and heavier.
Dr. Zellmer
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.osu.edu/pipermail/cbc-chem1220/attachments/20230419/7fbd413c/attachment-0001.html>
More information about the cbc-chem1220
mailing list