Colligative Properties and "i"
robert zellmer
zellmer.1 at osu.edu
Sat Sep 2 09:37:55 EDT 2017
You can find the following information at following link in case you
lose this e-mail (part of the "Helpful Tidbits" link), *Colligative
Properties*
<http://chemistry.osu.edu/%7Erzellmer/chem1220/faq/collig_prop.txt>
This message deals with colligative properties. Hopefully this helps
those of you having problems with this and the equations, especially the
"i" in the equations I used in class. These equations are below: del Tb
= i*Kb*m del Tf = i*Kf*m P = i*M*R*T This "i" is: 1 for a
nondissociating or nonionizing substance (this is most molecular
substances, with the exception of acids & bases) # ions from the formula
for an "ideal" ionic solution (this means no interionic association,
i.e. "ion-paring") i*m = molality of particles i*M = Molarity of
particles For a NONelectrolyte (nondissociating or nonionizing compound)
the "i" is 1 (dissolves as a single particle). This is true for most
molecular substances, which dissolve as a single particle and don't
ionize (there are some that do, particularly acids - see below). For an
electrolyte (a compound that dissociates or ionizes and gives more than
1 particle in solution) the 'ideal' "i" is given by the number of
particles resulting from the formula. For NaCl i=2 since you get 2
particles per formula unit (Na^+ and Cl^- ). For Na2SO4 i=3 since you
get 3 particles per formula unit (2 Na^+ and 1 SO42-, the SO42- stays
together as a single particle). These are the "ideal" values for "i".
When I speak of an "ideal" ionic solution it means to use the "ideal"
value for "i" (i.e. the "i" you get from the formula). An "ideal" ionic
solution has no ion association (does not form ion pairs). Usually when
we speak of the van't Hoff factor we are referring to an observed or
effective "i". The actual number of effective particles in solution is
less than the ideal "i" you get from the formula unit and varies with
the concentration of the electrolyte, approaching the ideal "i" for
dilute solutions. You can calculate this observed "i" when given the
observed colligative property and molality or molarity. This behavior is
due to interionic attractions between the ions in the solution leading
to the formation of ion pairs. This reduces the number of independent
particles. While I've mentioned ionic substances above this also applies
to molecular substances that ionize in solution. These are mostly acids
and bases such as HCl, HNO3, NH3 (base), acetic acid, etc. The strong
acids you learned in chapter 4 (table 4.2) are strong electrolytes and
come apart in H2O, like ionic substances do. So HCl has an ideal "i" of
2. Weak acids (and bases) do not completely ionize so only some of them
come apart. This makes determining an ideal "i" very difficult. An
example of a weak acid is acetic acid, CH3CO2H. This molecule is a weak
electrolyte and does not completely ionize. So we can't say with
certainty what "i" is. The most one can say is it's somewhere between 1
and 2 (1 if it didn't ionize and 2 if it completely ionized). Thus, for
the same stated conc. of solute, for acetic acid one can say it has a
larger effect than something like glucose, C6H12O6, which doesn't ionize
in H2O (i=1) and a smaller effect than something like HCl or NaCl which
completely ionize or dissociate (ideal i=2) . Of course an observed "i"
(van't Hoff factor) can be calculated for acetic acid. This is one of
the ways we determine how much acetic acid actually ionizes (as we will
discuss further in chapter 16). Also, remember the van't Hoff factor
varies with conc. The things I've just said apply to all the colligative
properties. You may have noticed that you didn't see an "i" in the vapor
pressure lowering equations. Unlike molarity or molality, X_part is not
exactly equal to i*X_stated, i.e. a NaCl solution with a mole fraction
of 0.4 NaCl will not simply be 0.8 mole fraction in particles (2*0.4).
The actual mole fraction of particles (ions) for this NaCl solution is
0.57 (not 0.8). However, even though the mole fraction of particles
can't strictly be determined from multiplying the mole fraction of a
substance times "i", it can be approximated as such (especially as the
solution becomes more dilute) and you can still use these principles for
comparing the vapor pressure lowering of several substances. There is
actually a formula you can derive (prove this for yourself) that gives
the mole fraction of ions: i * X_solute X_ions =
-------------------------- X_solvent + i * X_solute Dr. Zellmer
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