# 14 again!

[Robert Zellmer]

The answer is actually A.  Let me explain why.

When I replied before I was in a hurry (had to visit my 1250 labs
before they got too far along) and just looked at one of my
previous iterations of the exam and saw the answers and the numbers.
Just to give you a background on how I do it (now, don't tell anyone else
since this is a trade secret), I pick out many questions from various test
banks and make up some and make up an initial  exam, often times with
50 or more questions.  Then whittle it down to the ones I want, a long
and tedious process.   When I saw a couple of e-mails about #14 I pulled
up an exam.  Unfortunately I pulled up one of the intermediate iterations
of the exam and in trying to fix a "problem" quickly maybe made it worse.

I got another e-mail after the previous and decided to find my original
master exam and rework the problem just to make sure.  The answer is A.

The reaction given is the reverse of the formation reaction and multiplied
by 2.  You need to change the sign of the delG_f given and multiply it by
two.  To be honest with you I didn't realize (c) was the answer if you 
didn't
multiply by two.

I've had some questions about a few other problems.  I will answer those
in due time in one e-mail to the whole class since many seem to have the
same questions.

Dr. Zellmer