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<p class="MsoNormal"><span style="font-family:"Arial",sans-serif">Someone asked about problem 17.68 in the 13th & 14th eds. (17.66 in 12th ed.,
<br>
17.62 in 11th ed., 17.60 in 10th ed). The solution manual adds 3 equations <br>
together to get an eqn and then add H+ to both sides to get the actual <br>
final eqn. However, when they did this they didn't do it as adding another <br>
reaction eqn and accounting for the K for this added reaction. <br>
<br>
It should have been done by adding a 4th eqn, the reverse of the self-ionization <br>
eqn for H2O and including 1/Kw in the final calculation for the K. I've corrected
<br>
it the best I could by editing a PDF file and attached that. <br>
<br>
Dr. Zellmer <o:p></o:p></span></p>
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